Charlotte's Web (filem 1973): Béda antara owahan

Konten dihapus Konten ditambahkan
c sithik
Larik 22:
Aanak-anak babi lair ing kebun tetanèné John Arable. Salah siji wujudé kerdil mula John arep mungkasi anak babi kerdil mau. Nanging, anak wadoné, Fern Arable, bareng krungu nasib anak babi mau banjur ngupaya nylametaké lan matur marang bapaké yèn arep matèni anak babi amarga ukurané luwih cilik tinimbang liyané iku tumindak sing konyol. Fern ngurusi anak babi cilik mau lan maringi jeneng "Wilbur". Sawisé enenm minggu, John Arable ngandhani Fern yèn wis wektuné kanggo ngedol (10&nbsp;sedulur babiné wis kadol). Fern susah lan ngucapaké pepisahan marang anak babiné sing dituku déning paklik-é, Homer Zuckerman. <!-- When Wilbur wants to play with a lamb, the lamb's father (known as a ram) says that sheep don't play with pigs because it's only a matter of time before they are turned into smoked bacon and ham. Wilbur starts crying, saying that he doesn't want to die, but a voice from above tells him to "chin up". The next day she sings a song about "chinning up", and reveals herself to be a spider named Charlotte. She saves Wilbur by writing messages in her web, hence the title. She eventually dies, and although 511 of her children leave the barn (she had 514), three of them stay. But as much as Wilbur loves them, they will never replace the memory of Charlotte. -->
 
== Pranala jabanjaba ==
* {{imdb title|0070016|Charlotte's Web}}